538
-247
------
8-7=1
Cross out 5 and make it 4. Make 3 into 13. 13-4=9
4-2=2
The answer is: 291
Answer:
-31
Step-by-step explanation:
We need to use BODMAS to figure out the answer to this extremely difficult question:
So first we need to multiply:
-7 × 6 = -42
Then we need to add:
2 + 4 + 5 = 11
Now we need to subtract:
11 - 42 = -31
Answer:
Area = 64π
Area \: = \pi {r}^{2}Area=πr
2
64 \: \pi \: = \pi {r}^{2}64π=πr
2
{r}^{2} = \dfrac{64\pi}{\pi}r
2
=
π
64π
{r}^{2} = 64r
2
=64
r \: = \: \sqrt{64} = 8r=
64
=8
Radius = 8 units
Finding the Diameter -
Diameter = Radius x 2 = 8 x 2 = 16 .
\bold{Diameter \: is \: 16 \: units}Diameteris16units
Answer: It will take Damon 6 weeks to save the money he needs to buy the snowboard
Step-by-step explanation:
First, let's see what the problem is giving us:
-The variable X will represent the number of weeks it will take Damon to save the money he needs.
- Damon has $40
- Damon is going to safe $20 weekly
- The snowboard costs $160
Therefor:
Our equation will be: $40 + $20X = $160
Step 1
We need to isolate the variable by subtracting in both sides of the equation 40 in order to maintain the equality.
40 - 40 + 20X = 160 - 40
This will let us with 20X = 120
Step 2
We have to isolate the variable again, but this time (because the variable is being multiplied by 20) we have to divide on both sides of the equation.
20X/20 = 120/20
Therefore: X=6
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So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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