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Mashutka [201]
3 years ago
12

Suppose that in individual has a body fat percentage of 19.3% and weighs 126 pounds how many pounds of weight is made up of fat

round your answer to the nearest tenth
Mathematics
1 answer:
Inga [223]3 years ago
4 0
This is a relatively easy question to solve. You want to find 19.3% OF 126, meaning that you have to use multiplication. So you would do 126*0.193 which would equal 24.318 which can be rounded to 24.3
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Your having lunch at Taco Bell. You have your choice of a taco,burrito or Mexican pizza. You can choose between rice and beans.
tino4ka555 [31]

Let T be the taco, B the burrito, MP the mexican pizza, R the rice, and N the beans.

For the main course we can have the first three.

----- T

------ B

-------MP

Each main course comes with the two sides. So an R branch and a B branch go to each of the taco, burrito, or pizza.

-----T---------R or N.

We expand it to

--------T-----------R

---------------------N

And we repeat it for the rest.


Thus, the tree diagram is

----- T --------R

-----------------N

-----B---------R

-----------------N

----MP--------R

----------------N

5 0
3 years ago
Read 2 more answers
Need help with this one also
-Dominant- [34]

Answer:

D

Step-by-step explanation:

10/7 = 1.4285

9/y = 1.4285

Multiply both sides by y.

9 = 1.4285y

Divide both sides by y.

6.3 = y

6 0
2 years ago
The difference of a number x and 5.
DiKsa [7]

Answer:

Below

Step-by-step explanation:

Difference= ‘-’

=

x - 5

3 0
3 years ago
HELPPP PLEASE I NEED AN ANSWER
mina [271]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
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