<img src="https://tex.z-dn.net/?f=7y%20%5Ctimes%204x%20-%205x%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="7y \times 4x - 5

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3 years ago

7

x {?}^{2} " alt="7y \times 4x - 5x {?}^{2} " align="absmiddle" class="latex-formula">

1 answer:

lapo4ka [179]3 years ago

5 0

The answer is i don’t know or I don’t care and what are we trying to find

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What is the equation of the circle with center (0, 0) that passes through the point (-8, 3)?

77julia77 [94]

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>

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3 years ago

Kindly answer this one. Thank you.

steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦ The midline's length is the average of the lengths of the top and bottom parallel sides.

$AL=\frac{OR+CE}{2}$

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

$x=\frac{9+5}{2}=7$

2. AL = <em>m</em> - 4, CE = 15, OR = 17

$m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16$

3. OR = y + 5, AL = 15, CE = 18

$15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12$

4 0

2 years ago

37,831 thousand in standard form

saveliy_v [14]

30 000 + 7 000 + 800 + 30 + 1

8 0

3 years ago

Read 2 more answers

Jim connected the points with line segments to form a polygon. witch point is located inside the polygon

Studentka2010 [4]

Answer:

Step-by-step explanation:

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2 years ago

How much smaller is the sum of the first 1000 natural numbers than the sum of the first 1001 natural numbers?

aleksandr82 [10.1K]

ANSWER

1001

EXPLANATION

The sum of the first n - natural numbers is

$S_n= \frac{n}{2} (2a + d(n - 1))$

The sum of the first 1000 terms is

$S_{1000}= \frac{1000}{2} (2(1) + 1(1000 - 1))$

$S_{1000}=500 (1001)$

$S_{1000}=500500$

The sum of the first 1001 terms is

$S_{1001}= \frac{1001}{2} (2(1) + 1(1001 - 1))$

$S_{1001}= 1001 \times (501)$

$= 501501$

The difference is

$501501 - 500500= 1001$

5 0

2 years ago

Read 2 more answers