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3 years ago

Please help me With number 26

Mathematics

1 answer:

allochka39001 [22]3 years ago

3 0

Answer:

$540

Step-by-step explanation:

$0.36×1500

= $540

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Arithmetic sequence help!!!

LenKa [72]

Note that you are subtracting 6 each time.

5 terms have been shown.

Multiply -6 with 7 (as you are trying to find the 12th term)

-6(7) = -42

Add - 42 with -25

(-42) + (-25) = -67

(D) -67 is your answer

hope this helps

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3 years ago

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The diagram shown is a cube. If a plane slices horizontally through the solid, what is the shape of the cross-section?

gregori [183]

Answer:

its C Square

Step-by-step explanation:

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4 years ago

How do i write 2,009,345 in word form?

Rom4ik [11]

Two million, nine thousand three hundred forty five

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4 years ago

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Select all the lines that have a slope of 5/2.

Volgvan

Answer:

A rate of 5/2 means that:

If we move 2 units to the right, we move 5 units up.

Let's see all the graphs, the easier way to know this is:

In any point of the line, move to the right 2 units.

Then from that point, move up until you meet again with the line, if you moved 5 units, then the slope is 5/2.

A) The slope is 5/2.

B) The slope is 4/2

C) the slope is 5/2

I can not see very well graphs E and D in the image.

E) may have a slope of 5/2, you should measure it.

D has not a slope of 5/2, you can compare it with A and see that is totally different, so you can discard option D.

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3 years ago

g Suppose that the populationy(t)of a certain kind of fish is given by the logistic modely′= 3y−2y2(a) Solve the Bernoulli equat

Ksju [112]

Answer:

y = $\frac{3}{2 + 3Ce^{-3t} }$

Step-by-step explanation:

As given , y' = 3y - 2y²

⇒y' - 3y = -2y²

Divide by y² in the above equation

⇒ $\frac{y'}{y^{2} } - \frac{3y}{y^{2} } = -\frac{2y^{2} }{y^{2} }$

⇒ $\frac{y'}{y^{2} } - \frac{3}{y } = -2$ ........(1)

Now , let $\frac{1}{y}$ = u

⇒- $\frac{1}{y^{2} } \frac{dy}{dt} = \frac{du}{dt}$

⇒- $\frac{1}{y^{2} }y' = \frac{du}{dt}$

∴ equation (1) becomes

- $\frac{du}{dt}$ - 3u = -2

⇒ $\frac{du}{dt}$ + 3u = 2

It is a linear differential equation

Now,

Integrating factor = I.F = $e^{\int\limits {3} \, dt }$ = $e^{3t}$

∴ The solution becomes

u.(I.F) = $\int\limits {2.(I.F)} \, dt$ + C

⇒u.( $e^{3t}$ ) = $\int\limits {2.(e^{3t} )} \, dt$ + C

⇒u.( $e^{3t}$ ) = $\frac{2e^{3t} }{3}$ + C

⇒u = $\frac{2}{3} + Ce^{-3t}$

As $\frac{1}{y}$ = u

⇒ $\frac{1}{y}$ = $\frac{2}{3} + Ce^{-3t}$

⇒ y = $\frac{1}{\frac{2}{3} + Ce^{-3t} } = \frac{3}{2 + 3Ce^{-3t} }$

⇒ y = $\frac{3}{2 + 3Ce^{-3t} }$

6 0

3 years ago