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3 years ago

15

Glenda and penny are doing a sack race. Glenda jumps forward 18 inches each time she jumps. Each of Penny’s hops is 15 inches. H

ow far from the starting line will it be when Glenda and penny have both landed at the same distance ?

1 answer:

il63 [147K]3 years ago

3 0

I’m sorry I don’t have the answer but Glenda and Penny really need to figure out there problems

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Lines DE and AB intersect at point C.

alexandr402 [8]

Answer:

25

Step-by-step explanation:

2x+2+5x+3=180 (angles on a straight line)

7x+5=180

7x=180-5

7x=175

x=25 (dividing both sides by 7)

3 0

3 years ago

Will mark brainliest and 15 points

defon

Step-by-step explanation:

x + y = 9. => 2x + 2y = 18.

2x + 2y = 18

- (2x - 3y = -12)

=> 5y = 30, y = 6.

Therefore x + (6) = 9, x = 3.

The solution is x = 3 and y = 6.

7 0

3 years ago

PLEASE HELP!! Write an equation of g(x) that represents an exponential base “e” parent function with the following transformatio

Montano1993 [528]

Answer:

$g(x) = 12 {e}^{ - x - 7}$

Step-by-step explanation:

The parent function is

$g(x) = e {}^{x}$

First it is asked to reflect over the y axis so using the rule

$g(x) = g( - x)$

Our function looks like

$g(x) = e {}^{ - x}$

Then we are asked to shift the equation to the right 7. When shifting to the right or move the x axis, instead of adding 7 we would want to subtract 7 since the x axis is the independent variable and we must respect the y axis which is the dependent so using the rule

$g(x) = g(x - h)$

When subtracting a 7 it looks like now

where h is the number we move . Now we are asked to apply a vertical stretch of 12. Since vertical stretch refers to the y axis, we are just going to multiply the function by 12 using the rule

$g(x) = a \times g(x)$

where a is the vertical stretch. So now it would look like

$g(x) = 12 {e}^{ - x - 7}$

4 0

3 years ago

9n - 7 = 5n - 19<br> What is n and why did you do that

tamaranim1 [39]

14n=-26

i tried at least

5 0

3 years ago

Read 2 more answers

How many different right triangles are there with a hypotenuse of lenght 5 cm

Sveta_85 [38]

Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

ABC is a right triangle with hypotenuse 5. Do this again with a point a little closer to the 3 O’Clock position. It’s another right triangle with hypotenuse 5.

Indeed, as you get closer to the right, along the arc, the height of the triangle declines, but the width of the triangle increases. The hypotenuse remains 5 in all cases. We picked points on the circle. We could have picked points on the horizontal line first, and raised perpendicular lines until they intersected the circle. Each point forms a distinct right triangle.

There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

6 0

3 years ago