Formatting is kind of messed up. I'm assuming the differential equations is dy/dx = 6x
You need to get all the x's on one side and y'all on the other.
dy =6x dx
Integrate both sides.
y = 3x^2 + C
Now plug in the given values
y(0) = 4 = 3(0)^2 + C
C = 0
y = 3x^2
Plug 1 in for x to find the value of y(1)
y(1) = 3(1)^2 = 3
Answer:
11/7
Step-by-step explanation:
22/7 divided by 2 = 22/7 multiplyed by 1/2 = 22/14 = 11/7
I don't really know what the second sentence means, so plz tell me, but here 22/7 minus 2/3 is 52/21
Answer:
8.533333
Step-by-step explanation:
9^(−
1/
2
)+25−
1
2
+32^
(3/
5)
= 9
(−1
/2)
+25(−
1
/2)
+32
^(3
/5)
=0.333333+25^(−
1/
2)
+32
^(3
/5)
=0.333333+25
^(−1
/2)
+32
^(3/
5)
=0.333333+0.2+32^
(3/
5)
=0.533333+32
^(3
/5)
=0.533333+8
=8.533333
Answer:
The answer to your question is: 20°
Step-by-step explanation:
Data
m∠XZY = 40
m∠XZB = 20
Process
1.- Find the measure of ∠ XAB
∠XAB = 40° because AB ║ YZ
2.- Find the measure of ∠ZAB
∠ZAB + ∠XAB = 180
∠ZAB = 180 - ∠XAB
∠ZAB = 180 - 40
∠ZAB = 140°
3.- Find the measure of ∠ABZ
The sum of the internal angles in a triangle equals 180°
∠AZB + ∠ZAB + ∠ABZ = 180
20° + 140° + ∠ABZ = 180
∠ABZ = 180 - 20 - 140
∠ABZ = 20°
