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torisob [31]
3 years ago
15

Lester was solving an equation but he made a mistake. What is the mistake and what is the correct answer? X + 17 = 22 –22 –22 x

= 0
Mathematics
2 answers:
m_a_m_a [10]3 years ago
5 0

X + 17 = 22

- 17 - 17

X=5

Amiraneli [1.4K]3 years ago
3 0

subtract 17, not 22, from both sides. 17 – 17 = 0 and 22 – 17 = 5. The answer should be x = 5.

Step-by-step explanation:

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Arisa [49]

For this case we have that by definition of trigonometric relations of rectangular triangles, that the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle. So:

Sin (45) = \frac {leg} {h}

Where h is the hypotenuse.

\frac {\sqrt {2}} {2} = \frac {leg} {h}

We cleared h:

h = \frac {2leg} {\sqrt {2}}

We rationalize:

h = \frac {2leg} {\sqrt {2}} * \frac {\sqrt {2}} {\sqrt {2}}\\h = \frac {2 \sqrt {2} * leg} {2}\\h = \sqrt {2} * leg

ANswer:

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3 years ago
If two cards are randomly drawn from a standard 52-card deck, what is the probability that both cards are hearts?
Anettt [7]

Answer:

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Step-by-step explanation:

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4 years ago
Let s be the annual sales​ (in millions) for a particular electronic item. The value of s is 54.554.5 for 20062006. What does s​
Kobotan [32]

Answer:

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Step-by-step explanation:

The problem statement tells you the meaning of s. It doesn't change meaning when you give it a value.

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3 years ago
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

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3 0
3 years ago
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Sergio [31]

Given:

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To find:

The inverse of the given function, then draw the graphs of function and its inverse.

Solution:

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Step 2: Interchange x and y.

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Step 4: Substitute y=g(x).

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Therefore, the inverse of the given function is g(x)=\dfrac{x+3}{6} and the graphs of these functions are shown below.

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3 years ago
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