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torisob [31]
3 years ago
15

Lester was solving an equation but he made a mistake. What is the mistake and what is the correct answer? X + 17 = 22 –22 –22 x

= 0
Mathematics
2 answers:
m_a_m_a [10]3 years ago
5 0

X + 17 = 22

- 17 - 17

X=5

Amiraneli [1.4K]3 years ago
3 0

subtract 17, not 22, from both sides. 17 – 17 = 0 and 22 – 17 = 5. The answer should be x = 5.

Step-by-step explanation:

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Which of these is closest to the time in years that it will take an investment to triple when it is invested in an account that
kkurt [141]

Answer:

20.4 years

Step-by-step explanation:

The nper formula in excel comes handy in this scenario:

=nper(rate,pmt,-pv,fv)

Rate is the monthly rate of 5.4%/12

Assuming actual investment is $5,000 which is pv

The triple amount would be $5,000*3=$15,000 which is future value fv.

pmt is the regular cash flow the investment which is zero

=nper(5.4%/12,0,-5000,15000)= 244.68  months

Yearly it can be expressed as = 244.68/12  =20.39  years

When rounded to one decimal place it becomes 20.4 years

5 0
3 years ago
What are the fourth roots of -3+3√3i?
barxatty [35]

Answer:

Set  

−

3

+

3

√

3

i

equal to  

0

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−

3

+

3

√

3

i

=

0

Since  

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3

+

3

√

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≠

0

, there are no solutions.

Step-by-step explanation:

3 0
3 years ago
How to solve 45 45 90 triangle given hypotenuse?
statuscvo [17]
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.
 
4 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
tom had a very challenging fraction multiplycation problem to do, but his sister said it was really easy to do mentally. can you
krok68 [10]

Answer:

76/81×80

76=80/81

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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