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Kay [80]
3 years ago
6

A race car travels 400 km in a time of 2 hours. Determine the speed of the race car

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

200km per hour

3.33km per second

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HELP!!
leonid [27]

Answer:

The focus point is (2 , 0) ⇒ answer D

Step-by-step explanation:

* Lets revise the equation of the parabola in standard form

- The standard form is (x - h)² = 4p(y - k)

- The focus is (h, k + p)

- The directrix is y = k - p

- If the parabola is rotated so that its vertex is (h , k) and its axis of

 symmetry is parallel to the x-axis, it has an equation of

 (y - k)² = 4p(x - h)

- The focus is (h + p, k)

- The directrix is x = h - p

* Lets solve the problem

∵ The equation of the parabola is y = 1/8(x² - 4x - 12)

- Lets make x² - 4x completing square

∵ √x² = x  

∴ The 1st term in the bracket is x

∵ 4x ÷ 2 = 2x

∴ The product of the 1st term and the 2nd term is 2x

∵ The 1st term is x

∴ the second term = 2x ÷ x = 2

∴ The bracket is (x - 2)²

∵  (x - 2)² = (x² - 4x + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out  

  the bracket to keep the equation as it

∴ (x² - 4x + 4) - 4 = (x - 2)² - 4

- Lets put the equation after making the completing square

∴ y = 1/8 [(x - 2)² - 4 - 12]

∴ y = 1/8 [(x - 2)² - 16] ⇒ multiply both sides by 8

∴ 8y = (x - 2)² - 16 ⇒ add 16 to both sides

∴ 8y + 16 = (x - 2)² ⇒ take from the left side 8 as a common factor

∴ 8(y + 2) = (x - 2)²

∴ The standard form of the equation of the parabola is

   (x - 2)² = 8(y + 2)

∵ The standard form of the equation is (x - h)² = 4p(y - k)

∴ h = 2 , k = -2 , 4p = 8

∵ The focus is (h , k + p)

∵ h = 2

∵ 4p = 8 ⇒ divide both sides by 4

∴ p = 2

∴ The focus = (2 , -2 + 2) = (2 , 0)

* The focus point is (2 , 0)

6 0
3 years ago
Find the distance between (-3, 11) and (-6,4).Round to the nearest then the
Likurg_2 [28]

Answer:

d =7.6

Step-by-step explanation:

(-3,11) =(x_1,y_1)\\(-6,4)=(x_2,y_2)\\\\\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\=\sqrt{\left(-6-\left(-3\right)\right)^2+\left(4-11\right)^2}\\= \sqrt{(-6+3)^2+(4-11)^2}\\ \\d= \sqrt{(-3)^2+(-7)^2} \\\\d = \sqrt{9+49}\\ \\d = \sqrt{58}\\\\d = 7.61577\\\\d =7.6

3 0
3 years ago
Find 4 geometric means between -5 and -125.
balandron [24]

The geometric means between -5 and -125 is; 25

<h3>How to find the geometric mean?</h3>

To find the geometric mean between two numbers, we simply find the square root of the product of the two numbers.

For example, geometric mean between A and B is;

G.M = √(A * B)

Thus, geometric mean between -5 and -125 is;

G.M = √(-5 * -125)

G.M = √625

G.M = 25

There could be other geometric means between this like;

G.M = √(-5 * -45) = 15

Or GM = √(-10 * -40) = 20

Read more about geometric mean at; brainly.com/question/17266157

#SPJ1

8 0
1 year ago
State whether the following is perpendicular or parallel y=(1/2)×y=-2×+9​
Rom4ik [11]

Answer:

parallel!

Step-by-step explanation:

if you insert the equation into demos there parallel

3 0
2 years ago
Another Algebra problem i am too stupid to do
VARVARA [1.3K]
5 (x+4) ...................
8 0
2 years ago
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