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Romashka [77]
3 years ago
5

- A bakery received 2 shipments of

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

1.88 pounds

Step-by-step explanation:

First, find the total amount of sugar, since there were 2 shipments

22.56(2)

= 45.12

Then, divide this by 24:

45.12/24

= 1.88

So, each canister had 1.88 pounds of sugar

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Solve for x in the equation:<br> x^2 - x = 20
max2010maxim [7]
X=5
cuz 5^2=25
25-5=20
8 0
3 years ago
The product of a number t and 6 increased by 1 is equal to 43
Flura [38]
6*7=42 42+1=43 therefore the number you are looking for is 7
5 0
3 years ago
HELP PLEASE IM BEGGING YOU
andriy [413]

Answer:

75th term in the sequence is 227.

Step-by-step explanation:

75 term of A.P is

a_75= a+ (n-1)d

Given series is 5,8,11,14.

hence a= 5 d= 8-5 = 3 , a_75.

a_75 = 5+(75-1)3

= 5+ (74)3

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6 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
4 years ago
(5pg)3=125pg. Is wrong or correct
irakobra [83]

Answer:

125 p^3 g^3

Step-by-step explanation:

(5pg)^3

We know that (ab)^c = a^c * b^c

5^3 p^3 g^3

125 p^3 g^3

4 0
3 years ago
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