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Archy [21]
3 years ago
9

Fifteen 2 inch nails weigh 35 grams. How many of these nails weigh 175 grams? Can you explain how to do this please thankyou so

much
Mathematics
1 answer:
polet [3.4K]3 years ago
8 0
Solving:

1) Pass: Make the rule three (Directly proportional) 

Two inch nails ______ grams (<span>Weight)
</span>15 ----------------------------35
n ----------------------------- 175

2) Pass: <span>Multiply cross
</span>
35*n = 15*175

3) Pass: Simplify
35*n = 15*175
35n = 2625
n =  \frac{2625}{35}
\boxed{n = 75}

Answer:
75 nails weigh 175 grams



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Answer:

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Step-by-step explanation:

a) Since order is not important, the total possible number of ways to choose 10 players out of 13 is the following combination:

C(13,10)=\frac{13!}{(13-10)!10! } \\C(13,10)=\frac{13*12*11*10!}{(3*2*1)10! }\\C(13,10) = 286

b) The total number of possibilities to assign positions by the selecting 10 players is the permutation of 13 players for 10 positions:

P(13,10) = \frac{13!}{(13-10)!}\\P(13,10) = 13*12*11*10*9*8*7*6*5*4\\P(13,10) =1,037,836,800

c) The number of ways to pick 10 players including at least one woman is equal to the total number of ways to pick 10 players (found in item a) minus the the number of ways to pick 10 players without picking a single woman.

Since there 10 male players for 10 positions, there is only one possible way to pick a team without women, therefore:

P=286-1 =285

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