1/6 divided by -2/9 PLEASE HELP!!!

Look at mina's work below 10 7/12 - 9/12 = (10/12 + 7/12) - 9/12 = 17/12 - 9/12 = 8/12 is mina's solution reasonable. Explain

RSB [31]

10 7/12 - 9/12=(10/12+7/12)-9/12=17/12-9/12=8/12

127/12-9/12

Nope. Her solution doesn't seem reasonable. In order to subtract 9/12 from 10 7/12 you must convert 10 7/12 to an improper fraction. You should then have 127/12 where she has 10/12.

Hope this helps! =)

8 0

2 years ago

This image shows a reconstruction of pyramid with a square base what is the best estimate for the volume of the pyramid

goblinko [34]

The answer fam is .........2,433,400 m3

7 0

3 years ago

Read 2 more answers

13 of the 18 players on the varsity soccer team are seniors. What percent of the players on the team are not seniors?

N76 [4]

They are about 27 percent that are not seniors

4 0

2 years ago

Read 2 more answers

In the figure, . Find x and y.

zloy xaker [14]

Answer:

The answer to your question is x = 52° and y = 137°

Step-by-step explanation:

Process

1.- Find the value of x using the large right triangle, remember that the sum of the internal angles in a triangle equals 180°.

x + 38 + 90 = 180

x = 180 - 90 - 38

x = 52°

2.- To find y, we notice that x and y -9 are supplementary angles so their sum gives 180°.

x + y - 9 = 180

Substitution

52 + y - 9 = 180

y = 180 + 9 - 52

y = 137°

6 0

3 years ago

Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

polet [3.4K]

Answer:

(a) The probability that X is at most 30 is 0.9726.

(b) The probability that X is less than 30 is 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.

Step-by-step explanation:

We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.

Let X = the number among these that are nonconforming and can be reworked

The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).

Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.

Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).

So, the new mean of X, $\mu$ = $n \times p$ = $200 \times 0.11$ = 22

and the new standard deviation of X, $\sigma$ = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{200 \times 0.11 \times (1-0.11)}$

= 4.42

So, X ~ Normal( $\mu =22, \sigma^{2} = 4.42^{2}$ )

(a) The probability that X is at most 30 is given by = P(X < 30.5) {using continuity correction}

P(X < 30.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{30.5-22}{4.42}$ ) = P(Z < 1.92) = 0.9726

The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.

(b) The probability that X is less than 30 is given by = P(X $\leq$ 29.5) {using continuity correction}

P(X $\leq$ 29.5) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{29.5-22}{4.42}$ ) = P(Z $\leq$ 1.70) = 0.9554

The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 $\leq$ X $\leq$ 25) = P(X < 25.5) - P(X $\leq$ 14.5) {using continuity correction}

P(X < 25.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{25.5-22}{4.42}$ ) = P(Z < 0.79) = 0.7852

P(X $\leq$ 14.5) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{14.5-22}{4.42}$ ) = P(Z $\leq$ -1.70) = 1 - P(Z < 1.70)

= 1 - 0.9554 = 0.0446

The above probability is calculated by looking at the value of x = 0.79 and x = 1.70 in the z table which has an area of 0.7852 and 0.9554.

Therefore, P(15 $\leq$ X $\leq$ 25) = 0.7852 - 0.0446 = 0.7406.

5 0

2 years ago

1/6 divided by -2/9PLEASE HELP!!!