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Brrunno [24]
3 years ago
8

Please help with this!!

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

ok

Step-by-step explanation:

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Help ASAPPPPP PLEASE!
lilavasa [31]

Answer:

1. 5 3/8

2. 3 7/12

3.7 11/15

4. 1 5/8

5. 6 8/12

6.2 7/15

7. 5 7/12

8. 6 1/3

Step-by-step explanation:

Hope this helps have a great day Sry if I got any wrong

4 0
3 years ago
Read 2 more answers
Solve the equation `x^{4}+13x^{2}+36=0` for all values of `x`.
Zolol [24]

Answer: x4+13x2+36=0

Step-by-step explanation:

Let's solve your equation step-by-step.

x4+13x2+36=0

Step 1: Factor left side of equation.

(x2+4)(x2+9)=0

Step 2: Set factors equal to 0.

x2+4=0 or x2+9=0

7 0
3 years ago
Evaluate 9.1s + 8.5t when s= 6 and t=7.
timurjin [86]

Answer:

The answer is 114.1.

Step-by-step explanation:

You have to substitute the s and t value into the expression :

9.1s + 8.5t

let \: s = 6

let \: t = 7

9.1(6) + 8.5(7)

= 54.6 + 59.5

= 114.1

3 0
3 years ago
A tank in the shape of an inverted right circular cone has height 6 meters and radius 3 meters. It is filled with 2 meters of ho
ANTONII [103]

Answer:

Step-by-step explanation:

Given

Radius of cone R=3\ m

height of cone H=6\ m

Chocolate is filled up to a height of h=2\ m

Work done to lift a body to a height h when F force is applied is  given by

W=Fh

An infinitesimally slice of chocolate \Delta y at a height of y has a radius

r=\dfrac{R}{H}\cdot h

Volume of slice is dV=\pi r^2y

mass =\rho \times dV

This mass need to be raised to a height of 6-y which requires a work of

dW=\rho (\pi r^2ydy)g(6-y)

To empty the tank

W=\int_{0}^{3}\rho \cdot \pi \cdot g\cdot r^2\cdot (6-y)dy

at h=y

r=\dfrac{R}{H}\cdot y

r=\dfrac{3}{6}y

r=\dfrac{y}{2}

W=\int_{0}^{3}\rho \cdot \pi \cdot g\cdot \dfrac{y^2}{4}\cdot (6-y)dy

W=10^3\times \pi \times \dfrac{1}{4}\times (2y^3-\dfrac{1}{4}y^4)_0^3

W=259.80\ kJ

4 0
3 years ago
2x-3y=-11. 3x+2y=20 system of equations I'm not good at these at all I still can't solve any of them
baherus [9]
Okay, so you what you would is solve one equation for Y=mx+b and then substitute this equation for Y so the answer would be Y=-3/2x + 20
And then you would do 2x-3(-3/2x+20)=-11 and you solve it for x
But to get y you would substitute what you got for x into ether equations.
5 0
3 years ago
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