Trinomial 2x² + 4x + 4.
It's of the form ax²+bx+c and it's discriminant is Δ=b² - 4.a.c
(in our case Δ = 4² - (4)(2)(4) → Δ = - 32
We know that: x' = -1 + i and x" = -1 - i
If Δ > 0 we have 2 rational solutions x' and x"
If Δ = 0 we have1 rational solution x' = x"
If Δ < 0 we have 2 complex solutions x' and x", that are conjugate
In our example we have Δ = - 16 then <0 so we have 2 complex solutions
That are x'= [-b+√Δ]/2.a and x" = [-b-√Δ]/2.a
x' =
Solving for L:
P = 2L + 2W
P - 2W = 2L
(P - 2W) / 2 = L
L = (P - 2W) / 2
F(g(x)) = 2(5x+1)-6 = 10x+2-6 = 10x-4
g(f(x)) = 5(2x-6)+1 = 10x-30+1 = 10-29
10x-4>10-29 because from f(g(x)) you subtract less quantity.
The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.
The answer is 292, if you need to show work let me know