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VikaD [51]
3 years ago
13

15 POINTS!!! How do the rules for adding and subtracting signed decimals compare with the rules for adding and subtracting integ

ers? (If you answer this please make it simple)
Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

The rules for adding and subtracting signed decimals are almost the same as the rules for adding and subtracting integers. When dealing with decimals, you need to be especially aware that your decimal points are lined up so that you do not accidentally add or subtract in the wrong place.

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Which is the first step in simplifying the expression?
Elenna [48]
\dfrac{3}{2 +  \sqrt{2} }

To rationalise the denominator, this is a standard step:
= \dfrac{3}{2 + \sqrt{2} } \times  \dfrac{2 - \sqrt{2}}{2 - \sqrt{2}}

Answer: Option A

---------------------------------------------------------------------------------------------------

Let me continue to complete the question, though it is not ask for

= \dfrac{3(2 - \sqrt{2})}{(2 + \sqrt{2)}(2 - \sqrt{2}) }

= \dfrac{3(2 - \sqrt{2})}{4 - 2 }

= \dfrac{6 - 2\sqrt{2}}{2 }
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3 years ago
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Which points
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Answer:

5, 6 and 9 , 10 so E and F.

Step-by-step explanation:

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You are allowed to go to the store and spend your allowance on one of these three items: ball, candy, or hat. Which one would yo
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I would choose a hat, because it is stylish and can keep me warm. My opportunity cost would be a ball, because it is useful for boring, lonely days. This is what I would write, Idk if you like it or not.

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3 years ago
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What is 6(x-3) -4 (x-5)
vladimir1956 [14]

Answer:

2x + 2

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6(x - 3) - 4(x - 5)

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6 0
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What is 2(x + 4)=2(-8- x) - 2x
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Answer:

You want to solve for x, the first thing you need to do is distribute

The 2 through the x+4 then the other 2 through the -8-x

2(x+4)= 2x+8

2(-8-x)= -16-2x

2x+8=-16-2x-2x (combine like terms on the right side)

2x+8=-16-4x (now subtract 8 from each side)

2x=-24-4x (8-8=0, -16-8=-24) (now add 4x to each side)

6x=-24 (-4x+4x=0, 2x+4x=6x), (divide each side by 6)

x=-4 (6/6=1, -24/6=-4)

x=-4

Hope this helps ;)

6 0
3 years ago
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