$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\begin{array}{lllcll}
y=&6(x-&1)^2&-8\\
&\uparrow &\uparrow &\uparrow \\
&a&h&k
\end{array}$

5 0

3 years ago

Find the area of the rhombus. A= square units

Olin [163]

The answer should be 24 square units.

5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.

In order to do that, we need to use the Pythagorean Theorem.

a^2+b^2=c^2

3^2+b^2=5^2

9+b^2=25

Subtract 9 from both sides

b^2=16

Then square root both sides.

b=4.

Now that we have the base, you can then find the area of the triangle.

BH/2
4*3/2
12/2
6

So one triangle equals to 6. Then multiply that by 4 to find the area of the rhombus. Which would be 24 square units.

7 0

3 years ago