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Blizzard [7]
3 years ago
5

Which statement is true about a graph representing the data? Select two options​

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer:There isn’t any picture

Step-by-step explanation:

faust18 [17]3 years ago
4 1

Answer:

Where are the graph options??? lol

Step-by-step explanation:

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I got chu UwU, the answer is B cause it is smaller

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What is the radius and diameter of the following circle?
Cerrena [4.2K]

Answer:

Radius=9

Diameter=18

Step-by-step explanation:

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2 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
40 POINTS!!!!!!!! The length of a rectangle is 7 millimeters longer than its width. The perimeter is more than 62 millimeters.
Arte-miy333 [17]

a) L = W + 7  

b) 2 ( L + W ) > 62  

c) 2 ( W + 7 + W ) > 62  

2w+14+2w>62  

4w+14>62  

4w > 48  

w > 12

8 0
3 years ago
What is the sum of 2.5 x 10^4 and 3.4 x 10^4
navik [9.2K]

5.9 x 10^4

59000

That is the answer C

3 0
3 years ago
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