Which statement is true about a graph representing the data? Select two options

Mathematics

2 answers:

ch4aika [34]3 years ago

7 0

Answer:There isn’t any picture

Step-by-step explanation:

faust18 [17]3 years ago

4 1

Answer:

Where are the graph options??? lol

Step-by-step explanation:

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When you have > or <, the solutions are only in the shaded area. True or False

alexira [117]

Answer: True

Step-by-step explanation: Because the solutions can not land on the dotted lines.

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2 years ago

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The Naturally Made Bath and Body store pays $550 a month for rent and utilities. The average cost for its products to be manufac

skelet666 [1.2K]

To determine the equation to represent this situation, we can use 2.5x to show the amount of profit per product, and a y intercept value of -550 to show the cost for rent. Now, we have the equation y=2.5x-550.

The break even point is when the profits balance out the expenses, so in this case, y should equal 0.

0=2.5x-550

Add 550 to both sides...

550=2.5x

Divide both sides by 2.5...

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2 years ago

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. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

As we know:

$Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$