Answer:
X will be the number.
5 times that number X is 5X
2 less than 5 times the number is 5X - 2
Hope this helps! Plz mark brainliest! (づ ̄3 ̄)づ╭❤~
23) Store A: y=6.30÷2
y=3.15
Store B: y=3.2
Store C: y=3.25x
y=3.25 so Store A sells the cheapest so (A) is the answer
24) the area uses half of the diameter, not the whole diameter. so the answer is 5.5pi^2 (B)
25) 1/2 × 1/2 = 1/4 × 1/2 = 1/8 (D)
26) was done correctly and (D) is the correct answer
27) 2 (x-3) +1 =19
2 (x-3) = 19 - 1
(x-3) = 18 ÷ 2
x-3 = 9
x= 9+3
x=12 (D)
Answer:

tep-by-step explanation:
In order to find the integral:

we can do the following substitution:
Let's call

Then

which allows us to do convert the original integral into a much simpler one of easy solution:

Therefore, our integral written in terms of "x" would be:

Mine is protected view but it could be considered reading view although it might be editing view depending