It says only 20 points so I'm not helping
Subtract 2m from both sides : 4m + 3 = -2
Subtract 3 from both sides : 4m = -1
Divide by 4 on both sides : m = -1/4
A right angle is 90*
so 90/360 is da ansa XD ansa
There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees
Answer: True
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Work Shown:
Follow PEMDAS in reverse to solve for q
22q - 7 < 37
22q - 7+7 < 37+7 ... add 7 to both sides
22q < 44
22q/22 < 44/22 ... divide both sides by 22
q < 2