Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
DOMAIN:
- Set of allowable inputs (set of 1st elements of the ordered pairs in relation)
- X point
- AKA the input
DEFINE INPUT:
A number that'll be used in a function rule to determine the value of the output
RANGE:
- Set of possible outputs (set of 2nd elements of the ordered pairs in relation)
- Y point
- AKA the output
DEFINE OUTPUT:
Result of applying a function rule to the value of ani input
ORDERED PAIRS:
(-1, 7): -1 is the domain & 7 is the range
(3, 5): 3 is the domain & 5 is the range
(4, 9): 4 is the domain & 9 is the range
(-6, -10): -6 is the domain & -10 is the range
(-2, 8): -2 is the domain & 8 is the range
Hope this helps you!!! :)
7 is the value of x, and 64° is the measure of the unknown angle.
Triangle angles of 76°, (9x+1)°, and 40° are provided.
According to the triangle's "angle sum property," a triangle's angles add up to 180 degrees. Three sides and three angles, one at each vertex, make up a triangle. The sum of the interior angles in a triangle is always 180o, regardless of whether it is acute, obtuse, or right.
One of the most commonly applied properties in geometry is the triangle's angle sum property. Most often, the unknown angles are calculated using this attribute.
Now, the total of a triangle's three angles equals
76°+(9x+1)°+40°= 180°
⇒ 116+9x+1 = 180
⇒ 9x + 117 = 180
⇒ 9x = 63
⇒ x = 7
So, 9x+1=64°
As a result, x is equal to 7 and the unmeasured angle is 64°.
To learn more about the angle sum property of a triangle, refer to this link:
brainly.com/question/8492819
#SPJ1
THE EQUATION TO THIS PROBLEM IS y=2x+12
