For this case we have:
a)
to convert as a percentage we have:
* 100% = 10%
b)
, if we multiply the numerator and denominator by 25 we have:
c)
Now we must write a fraction that represents 50%.
We have. If we multiply the numerator and denominator by 50 we have:
Answer:
10%
Answer:
Abundance of isotope 79Br=51% and abundance of 81Br=49%
Step-by-step explanation:
We are given that
Mass of 79Br=78.9183 u
Mass of 81Br=80.9163 u
Average atomic mass of bromine=79.90 u
We have to find the relative abundance of the two bromine isotopes.
Let x be the abundance of 79Br
Then , abundance of 81Br isotopes=1-x
Average atomic mass=Mass of isotope(abundance of isotope)+Mass of other isotope(abundance of other isotope)
Using the formula
Percentage of isotope with abundance 0.51=%
Abundance of other isotope=1-0.51=0.49
Percentage of other isotope with abundance 0.49=%
Answer:
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That’s all I know hope it helps
Answer: 32°
Step-by-step explanation:
Complementary angles are the ankea that are equal to 90° when we add them together. This will then be:
9x+22 + 2x+24 = 90
11x + 46 = 90
11x = 90 - 46
11x = 44
x = 4
Angle F = 2x + 24
= 2(4) + 24
= 8 + 24
= 32°
The answer is 5 because 5(x) plus two equals seven and 5(x) subtracted by 2 equals 3