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Alex787 [66]
3 years ago
9

A piggy bank contains 35 coins.

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

Let d = number of dimes. Let q = number of quarters.

d + q = 35

A dime is worth 10 cents, or $0.1; d dimes are worth 0.1d.

A quarter is worth 25 cents, or $0.25; q quarters are worth 0.25q.

0.1d + 0.25q = 4.9

The system of equation is

d + q = 35

0.1d + 0.25q = 4.9

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It took Kelly 5 2/3 hours to fly from City A to City B then it took her another 2 3/5hours to fly from City B toCity C. Kelly fl
Vadim26 [7]

Answer:

eto na po

Step-by-step explanation:

5 2/3 × 2 3/5 = 5 6/15 answer

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2 years ago
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You were testing orange juice recipes it’s recipe calls for orange juice concentrate and water mix one has 4 cups of concentrate
Sav [38]

Answer:

First mixed is the most orangey.

Step-by-step explanation:

First:

Orange\ juice\ concentrate=4\ cups\\\\Water=6\ cups\\\\Tota\ content=4+6=10\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{4}{10}\times 100=40\%

Second:

Orange\ juice\ concentrate=1\ cups\\\\Water=3\ cups\\\\Tota\ content=1+3=4\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{1}{4}\times 100=25\%

Third:

Orange\ juice\ concentrate=2\ cups\\\\Water=4\ cups\\\\Tota\ content=2+4=6\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{2}{6}\times 100=33.33\%

First mixed has highest percentage of orange juice. Hence first mixed is the most orangey.

4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

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Vladimir79 [104]
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3 years ago
Please help me asap 25 points
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The answer to the math question

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