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ch4aika [34]
3 years ago
15

Solve for missing side of the a) 81 feet b) 63 feet c) 120 feet d) 168 feet

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0
I can’t see the data did you forget to put it or like forget to put a picture???
You might be interested in
Find two integers who’s sum is 20 and products is 100
ArbitrLikvidat [17]

Answer: 10

Step-by-step explanation:The answer is 10

Step-by-step explanation:

10+10=20

10 * 10= 100

Hope it helps you.

8 0
2 years ago
You must find the area of the shaded region in the link below
Mashutka [201]

Answer:

5x+1

Step-by-step explanation:

2x+3

*4x-5

=8x-15

Now you find the area of the white region

3x+2

*2-8

=3x+16

Now you subtract

8x-15

-3x+16

=5x+1

4 0
3 years ago
Read 2 more answers
9-5 1/2 x - 3 (-2x+1)
Stells [14]
First, distribute the -3(-2x + 1). 
-3 x -2x = 6x      -3 x 1 = -3       -3(-2x + 1) = 6x - 3
Now we have: 
9 - 5 1/2x + 6x - 3 
Combine like terms. 
-5 1/2x + 6x = 1/2x         9 - 3 = 6
The two terms we are left with are 1/2x and 6. 
The simplified version of this expression is 1/2x + 6. 
Hope this helps!
7 0
3 years ago
7 twelveths divided by 2 fifths.
9966 [12]

Answer: 1 11/24

<u>Do Keep Change Flip (KCF)</u>

Keep: 7/12

Change: ÷ into ×

Flip: 2/5 into 5/2

Your new problem should be 7/12*5/2

<u>Multiply</u>

7/12*5/2=35/24

<u>Turn 35/24 into a Mixed Number (Dvide)</u>

35÷24 = 1 11/24

5 0
3 years ago
Bit transmission errors between computers sometimes occur, where one computer sends a 0 but the other computer receives a 1 (or
lana66690 [7]

Answer:

(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010

(b)

(1 – p) = 0.010

(c)

E(x) = 25000 x 0.010

     = 259.2

Explanation has given below.

Step-by-step explanation:

Solution:

(a) Probability that a triplet is decoded.

2 out of three

P = 0.94, n = 3

m= no of correct bits

m   bit (3, 0.94)

At p(m≤1) = B (1; 3, 0.94)

 = 0.010

(b) Using your answer to part (a),

(1 – p) = 0.010

Error for 1 bit transmission error.

(c)  How does your answer to part (a) change if each bit is repeated five times (instead of three?

P( m ≤ 2 )

L = Bit (5, 0.94)

   = B (2; 5, 0.94)

   = 0.002

(d)  Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?

Given:

h = 25000

Bits are switched during transmission between two computers = 6% = 0.06

m = Bit (25000, 0.06)

E(m) = np

        = 25000 x 0.06

         = 1500

m = Bit (25000, 0.01)

E(m) = 25000 x 0.010

     = 259.2

3 0
3 years ago
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