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lbvjy [14]
3 years ago
7

What is 7 1/4 ÷ 6 1/35 =

Mathematics
1 answer:
prohojiy [21]3 years ago
7 0

Answer:

the answer is 1.20260 repeating

Step-by-step explanation:

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85 percent of 2500cm
Juliette [100K]

Answer:

2125

Step-by-step explanation:

of means multiply

85% * 2500

Change to decimal form

.85* 2500

2125

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3 years ago
Researchers conducted a study to find out if there is a difference in the use of ereaders by different age groups. randomly sele
ikadub [295]

No, there is significant difference in the use of e readers by different age groups.

Given sample 1 ( 29 years old) n_{1}=628, p_{1}=7%, sample 2( 30 years old)n_{2}=2309, p_{2}=0.11.

We have to first form hypothesis one null hypothesis and other alternate hypothesis.

H_{0}:π1-π2=0

H_{1}:π1-π2≠0

α=0.05

Difference between proportions p_{1}-p_{2}  =-0.04

p_{d}=0.07-0.11=-0.04

The pooled proportion needed to calculate standard error is:

p=(X_{1} -X_{2} )/(n_{1} +n_{2} )

=(44+254)/(628+2309)

=0.10146

The estimated standard error of difference between means is computed using the formula:

S_{p_{1} -p_{2} }=\sqrt{p(1-p)/m_{1}+p(1-p)/n_{2}  }

=\sqrt{0.101*0.899/628+0.101*0.899/2309}

=\sqrt{0.000143+0.00003}

=\sqrt{0.000173}

=0.01315

Z= Pd-(π1-π2)/S_{p_{1} -p_{2} }

=-0.04-0/0.013

=-3.0769

This test is a two tailed test so the p value for this test is calculated as (using z table)

p value:2 P(Z<-3.0769)

=2*0.002092

=0.004189

P value< significance level of 5%.

Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.

Learn more about hypothesis at brainly.com/question/11555274

#SPJ4

Question is incomplete as it also includes:

Significance level of 5%.

4 0
2 years ago
taneisha's family has signed up for a new cell phone plan.taneisha now has a limit on the number of texts she can send or receiv
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0 What is this question lol
5 0
3 years ago
In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate
pashok25 [27]

Answer:

The probability of getting an offspring pea that is green is is 0.733

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

Step-by-step explanation:

The formula for calculating the probability of an event is;

P = Favorable Outcome / Sample space

Let A be an event of getting an offspring green peas, B be an event of getting an offspring yellow peas and N be the total number of peas.

number of green peas in an offspring are 350

number of yellow peas in an offspring are 127

total number of peas are 477    

So in the genetic experiment, the number of times event A occurs is 350 and the number times event B occurs is 127

Now the probability of getting an offspring pea that is green is

P = number of green peas / total number of peas

p = n(A)/N

p = 350/477

p = 0.733

So YES, the probability is reasonably close to 3/4 ( 0.750 )

The probability of getting an offspring pea that is green is is 0.733.

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

5 0
3 years ago
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