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Diano4ka-milaya [45]
3 years ago
9

Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p

er 5 minutes of childcare. Which comparison of the childcare costs is accurate?
Gym B charges $1.05 less per hour than Gym A.
Gym B charges $1.50 less per hour than Gym A.
Gym B charges $5.25 less per hour than Gym A.
Gym B and Gym A charge the same hourly rate for childcare.
Mathematics
2 answers:
disa [49]3 years ago
5 0

The answer is D. Gym B and Gym A charge the same hourly rate for childcare.

Tomtit [17]3 years ago
3 0

Answer:

  Gym B and Gym A charge the same hourly rate for childcare

Step-by-step explanation:

The rate of $0.75 per 5 minutes is ...

  $0.75/(5/60 h) = $0.75×12/h = $9.00/h

Gym B's hourly rate is $9.00, the same as that of Gym A.

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Ivahew [28]
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4 0
4 years ago
Y is 5 times more than x
saw5 [17]

Answer:

y = 5x

Step-by-step explanation:

Form the equation:

y = 5 times x or y = 5x

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
4 years ago
Jose ordered some books online and spent a total of $133. Each book cost $8 and he paid a total of $5
Reika [66]

Answer:

16 books

Step-by-step explanation:

133$ - 5 dollars for shipping = 128$

128$ divided by 8 = 16

Therefore, the answer is 16 books.

7 0
4 years ago
Is calculating his expenses from his work trip to San Francisco. Below is the expense log he kept while traveling.
Alika [10]

Answer:

D

Step-by-step explanation:

379.00 - 15.00 + 154.00 x 3 + 65.00 + 13.00 = 904

0.55 x 63 = 34.65

34.65 + 904 = 938.65

5 0
3 years ago
Read 2 more answers
If you are able to answer this I’ll give most Brainly and I need it in about 20 min
nasty-shy [4]

okay, first to figure out the IQR of the table you need to organize them from least to greatest.

2.43, 6.14, 6.47, 7.19, 8.38, 8.63

to find the middle number of all of these you add them all together and divide by 6, which is the total amount of numbers there.

2.43 + 6.14 + 6.47 + 7.19 + 8.38 + 8.63 = 39.24

39.24 / 6 = 6.54

now that we have the IQR, next we find the outlier. to find the outlier you multiply the IQR by 1.5 which is 6.54 x 1.5 = 9.81 <- outlier

Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.

2.43 + 6.14 + 6.47 + 7.19 + 8.38 + 8.63 + 9.81 = 49.05

49.05 / 7 = 7.00 (Rounded)

I tried my best to solve this, sorry if it doesn't help.

6 0
3 years ago
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