Answer:
The numbers are 9, 19 and 76.
Step-by-step explanation:
Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.
The first number in terms of x:
The second number in terms of x:
If we add them all up, these 3 numbers in terms of x must be equal to 104, so:
Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:
The first number is 9, second number 19 and the third number 76.
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Looks like all real numbers except 1. It touch's all the y except 1 aka range
Answer:
Class 2 has 210 house points.
Step-by-step explanation:
630/3 = 210
1 = 210 x 2 = 420
2 = 210
420 + 210 + 630
Answer:
a = -1
Step-by-step explanation:
Combine like terms 6a + 5a = 11a
11a = -11
Divide -11 by 11
-11/11 = -1
