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3 years ago

Please help me solve this

Mathematics

1 answer:

Oduvanchick [21]3 years ago

3 0

$\dfrac{x}{ - 3} < - 4 \\\\ x > 12$

P. S. The inequality sign changed or flipped when there's a negative figure involved.

Hope this helps. - M

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The value of a machine when new is £8000. The value depreciates by 10% each year. Work out its value after 3 years

Sladkaya [172]

5,600

8000*.10(y)
8000*.10(3)
8000*.3
5600

8 0

3 years ago

Brice wants to build a table and put a border around it. The table and border must have an area of 3,006 square inches. The tabl

SVEN [57.7K]

B is the correct answer.

We are adding the border of x thickness to all 4 sides of the table. This makes the new width of the table 36+x+x = 36+2x and the new length of the table 72+x+x=72+2x. To find the area, we multiply the length and width:

(36+2x)(72+2x) = 3006

Multiplying the binomials, we get:
36*72 + 36*2x + 2x*72 + 2x*2x = 3006
2592 + 72x + 144x + 4x² = 3006

Combining like terms gets us
2592 + 216x + 4x² = 3006

Subtract 3006 from both sides:
2592 + 216x + 4x² - 3006 = 3006 - 3006
-414 + 216x + 4x² = 0

Writing in standard form we have
4x²+216x-414=0

8 0

3 years ago

Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used

ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes head start

Senn needs to give Ms. Beetle 18.4 minutes head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0

3 years ago

The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylind

Bess [88]

Answer:

12566.4 mm²

Step-by-step explanation:

The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.

TSA = Total Surface Area

CSA = Curved Surface Area

TSA of open cylinder = CSA of cylinder + area of base or top

= 2πrh + πr²

= πr(2h + r)

From the above question:

r = 50mm

h = 15mm

Hence,

= π × 50 (2 × 15 + 50)

= π × 50 (30 + 50)

= π × 50(80)

= π × 4000

= 12566.370614mm²

Approximately = 12566.4 mm²

The Surface Area of the petri dish with no lid = 12566.4 mm²

3 0

3 years ago

Plz help meh plz :}}

AVprozaik [17]

18 if it’s not, then 21. I did ratios i long time ago so i don’t fully remember them.

4 0

3 years ago

Read 2 more answers