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zhuklara [117]
3 years ago
5

What is 1 11/20 rounded to the nearest whole number

Mathematics
2 answers:
nadya68 [22]3 years ago
6 0
2 because 11/20 > 1/2.
g100num [7]3 years ago
3 0
It is 2 because 11/20 helps it round to the nearest whole number.
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If this angle is 1/6 of a rotation about a circle, then<br> its measure is
Nezavi [6.7K]

Answer:

60 degrees.

Step-by-step explanation:

A full rotation is 360 degrees.

So 1/6 is 360 * 1/6 =  60 degrees.

4 0
3 years ago
Can someone answer this
shepuryov [24]
Your answer for 15 is D or C. For 16 I’m estimating 125?
3 0
2 years ago
I need help with this math question
djyliett [7]
Percent means per one hundred so we can say that:

p/100≈(28)/(28+81+45+63+35)  guessing with my old eyes :)

p/100≈28/252

p≈2800/252

p≈11.11%

So rounded to the nearest 5% you'd have:

p≈10%
5 0
3 years ago
WILL MARK BRAINLIEST FOR CORRECT ANSWER!
kompoz [17]

Answer: the third option is the correct answer

Step-by-step explanation:

From the given right angle triangle,

The hypotenuse of the right angle triangle is 16√3

With m∠30 as the reference angle,

the adjacent side of the right angle triangle is x.

the opposite side of the right angle triangle is y.

To determine x, we would apply

the cosine trigonometric ratio.

Cos θ, = adjacent side/hypotenuse. Therefore,

Cos 30 = x/16√3

√3/2 = x/16√3

x = √3/2 × 16√3 = 3 × 8

x = 24

To determine y, we would apply

the Sine trigonometric ratio.

Sin θ, = opposite side/hypotenuse. Therefore,

Sin 30 = y/16√3

1/2 = y/16√3

y = 16√3 × 1/2

y = 8√3

4 0
3 years ago
The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, &amp; the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

5 0
2 years ago
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