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gogolik [260]
3 years ago
8

Can someone plz help me with dis i will give brainliest

Mathematics
2 answers:
Reil [10]3 years ago
8 0

Answer:

first one:  B and C

Second one: x=12, y=10 so the answer is B.

Step-by-step explanation:

First one: Irrational numbers are any numbers that go on forever in the decimal without ever repeating. Any square roots of numbers that aren't perfectly square, such as 4 and 9, are irrational. And anything with pi, or \pi, is always irrational.

Second one: 144 and 100 are perfect squares, meaning it can be created by multiplying the same number by itself, in this case 12 and 10. Subtract those and you get 2.

jarptica [38.1K]3 years ago
3 0

Answer:

the first one is b and c

step-by-step explanation:

You might be interested in
Please show work and thank you
Dimas [21]

Answer:

  55.36 m

Step-by-step explanation:

The Pythagorean theorem relates the side lengths of a right triangle. For legs 'a' and 'b', and hypotenuse 'c', it tells you ...

  c² = a² +b²

__

For this figure, that means ...

  ?² = 19² +52² = 361 +2704 = 3065

  ? = √3065 ≈ 55.36 . . . . meters

The missing side length is about 55.36 meters.

4 0
2 years ago
Find the y-intercept and x-intercept of the line.<br> -x+4y = 8
salantis [7]

Answer:

x-intercept(s):  ( − 8 , 0 )

y-intercept(s):  ( 0 , 2 )

Step-by-step explanation:

To find the x-intercept, substitute in  0  for  y  and solve for  x . To find the y-intercept, substitute in  0 for  x  and solve for  y.

7 0
3 years ago
Select the two values of x that are roots of this equation
Jet001 [13]
<h2>Hello!</h2>

The answers are:

B.   \frac{-3-\sqrt{29}}{2}

C.   \frac{-3+\sqrt{29}}{2}

<h2>Why?</h2>

We can use the quadratic equation to find the two values of x that are roots of the given equation. We must remember that most of the quadratic equations have two roots, however, we could find quadratic equations with just one root or even with no roots, at least in the real numbers.

Quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac} }{2a}

So,

From the given equation we have:

a=1\\b=3\\c=-5

Substituting it into the quadratic equation to find the roots, we have:

\frac{-b+-\sqrt{b^{2}-4ac} }{2a}=\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}\\\\\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}=\frac{-3+-\sqrt{9+20} }{2}\\\\\frac{-3+-\sqrt{29}}{2}

So,

x_{1}=\frac{-3-\sqrt{29}}{2}\\\\x_{2}=\frac{-3+\sqrt{29}}{2}

Hence, the correct options are B and C.

7 0
4 years ago
What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)
olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.  

For example:

Type of change               Effect on y = f(x)

y = f(x - c)                      horizontal shift: c units to right

So

Considering the function

f(x) = x^2

The graph is shown below. The first figure is representing f(x) = x^2.

Now, considering the function

\:f\left(x\right)=\left(x-6\right)^2

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of \:f\left(x-6\right)=\left(x-6\right)^2 is shown below in second figure. It is clear that the graph of  \:f\left(x-6\right)=\left(x-6\right)^2  is shifted 6 units to the right as compare to the function f(x) = x^2.

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

5 0
3 years ago
What is a number less than 400 but bigger than 312
Vikentia [17]
There are a lot of numbers that fall into that category...

Lets call your number x, then 400 < x < 312

That means x can be any number in between 400 and 312. But, x cannot be 400 or 312

x can be a total of 87 numbers which are listed here:

<span> <span><span> 313, </span> <span> 314, </span> <span> 315, </span> <span> 316, </span> <span> 317, </span> <span> 318, </span> <span> 319, </span> <span> 320, </span> <span> 321, </span> <span> 322, </span> <span> 323, </span> <span> 324, </span> <span> 325, </span> <span> 326, </span> <span> 327, </span> <span> 328, </span> <span> 329, </span><span>330, </span> <span> 331, </span> <span> 332, </span> <span> 333, </span> <span> 334, </span> <span> 335, </span> <span> 336, </span> <span> 337, </span> <span> 338, </span> <span> 339, </span> <span> 340, </span> <span> 341, </span> <span> 342, </span> <span> 343, </span> <span> 344, </span> <span> 345, </span> <span> 346, </span><span>347, </span> <span> 348, </span> <span> 349, </span> <span> 350, </span> <span> 351, </span> <span> 352, </span> <span> 353, </span> <span> 354, </span> <span> 355, </span> <span> 356, </span> <span> 357, </span> <span> 358, </span> <span> 359, </span> <span> 360, </span> <span> 361, </span> <span> 362, </span> <span> 363, </span> <span> 364, </span> <span> 365, </span><span>366, </span> <span> 367, </span> <span> 368, </span> <span> 369, </span> <span> 370, </span> <span> 371, </span> <span> 372, </span> <span> 373, </span> <span> 374, </span> <span> 375, </span> <span> 376, </span> <span> 377, </span> <span> 378, </span> <span> 379, </span><span>380, </span><span>381, </span> <span> 382, </span> <span> 383, </span> <span> 384, </span> <span> 385, </span> <span> 386, </span> <span> 387, </span> <span> 388, </span> <span> 389, </span> <span> 390, </span> <span> 391, </span> <span> 392, </span> <span> 393, </span> <span> 394, </span> <span> 395, </span> <span> 396, </span> <span> 397, </span> <span> 398, and </span> <span> 399. </span> </span></span>



5 0
3 years ago
Read 2 more answers
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