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kati45 [8]
3 years ago
11

If cos θ = -2/5 and tan θ > 0, what is the value of sin θ? PLEASE HELP!!!

Mathematics
1 answer:
goblinko [34]3 years ago
7 0
If cosФ<0 and tg Ф>0; then we are in the third quadrant, then sin Ф<0

Fundamental realtion of trygonometry:

sin²Ф+cos²Ф=1

Then:
sin Ф=⁺₋√(1-cos₂Ф):
Because we are in the third quadrant; sin Ф=-√(1-cos²Ф)

Sin Ф=-√(1-(-2/5)²)=-√(1- 4/25)=-√(21/25)=-√21 / 5

Answer: sin Ф=-√21 / 5

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Notice the table of values, thus let's pick two points from it, to check what the slope may be,

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3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
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SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
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3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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