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irga5000 [103]
3 years ago
7

Find the probability of a least one birthday match among a group of 44 people.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

0.1137= 11.37%

Step-by-step explanation:

Assuming there are 365 days in one year and every people have 1 birthday, then the chance for two people to have the same birthday is 1/365 and the chance they are not is 364/365. We are asked the chance for at least one match among 44 people. The opposite of the condition is that we have 0 matches and easier to calculate. The calculation will be:

P(X>=1)= ~P(X=0) = 1

P(X>=1)=- P(X=0)

P(X>=1)=1 - (364/365)^44

P(X>=1)=1- 0.8862

P(X>=1)=11.37%

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The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

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