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Arte-miy333 [17]
3 years ago
7

Expand the expression. 2/7(2s+3)

Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0
\frac{2}{7} (2s + 3) \\  \frac{4s}{7} +  \frac{6}{7}  \\  \frac{4s + 6}{7}
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Radda [10]

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we need help with the same thing

Step-by-step explanation:

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2 years ago
I got an answer, but I only got one mark help
kaheart [24]

Answer:

The answer 323.4 is pound.

Step-by-step explanation:

First 25% and 8% together which is 33%.Then find out 33% of 980.33/100×980=323.4 pound.

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3 years ago
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10. Explain why log328 is between 3 and 4.
maw [93]

Answer:

See explanation.

(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)

Step-by-step explanation:

I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.

3^0=1

3^1=3

3^2=9

3^3=27

3^4=81

3^5=243

......

I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.

log_3(28) means the value x such that 3^x=28.

Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.

8 0
3 years ago
Worth a lot of points! please help and explain your answer tysm
Arte-miy333 [17]

Answer:

option c is incorrect

because the value of tan B will be perpendicular/base

so tan B=5/12.

mark me brainlist

6 0
3 years ago
How many extraneous solutions does the equation below have?
aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S. 

The given equation consisting of  variable , m is

   \frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})

None of the two solution

m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2}), is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0
3 years ago
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