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3 years ago

What is 8(5x - 3y)=

Mathematics

2 answers:

Dmitrij [34]3 years ago

8 0

The answer is 40x - 24y

Monica [59]3 years ago

4 0

Answer:

40x-24y

You simplify through distribution

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1.)12.5+(-31.5)= 2.)-31.91+(-16.7)= 3.)1/6+(-11/12)+2/3= 4.)29+(-15.7)+(-31.05)=

Xelga [282]

1. = Step 1. Simplify Brackets and you get $12.5 - 31.5$ Step 2. Simplify and you get $-19
$ which is your answer.

2. = Step 1. Simplify Brackets and you get $-31.91-16.7$ Step 2. Simplify and you get $-48.61$

3. = Step 1. Simplify Brackets and you get $\frac{1}{6} - \frac{11}{12} + \frac{2}{3}$ Step 2. Simplify and you get $- \frac{1}{12}$

4. Step 1. = Simplify Brackets and you get $29-15.7-31.05$ Step 2. Simplify and you get $-17.75$

5 0

4 years ago

Convert into 9 kilogram into metre....

IrinaVladis [17]

Answer:

0.009000000000000001

5 0

4 years ago

Read 2 more answers

When I use 14 cat lovers to pet 350 cats, it takes 15 days. How long would it take to pet 480 cats if I use 18 cat lovers?

nika2105 [10]

I think it would take 16 days

6 0

3 years ago

Can anybody help me please I'm stuck with this question.

tekilochka [14]

Answer: 18 units

Step-by-step explanation:since its is a horizontal line x2 - x1

7 -1 = 6

line 2:

since this is a vertical line y2 - y1

7 - 3 = 4

line 3:

since this is a horizontal line x2 - x1

7 - 4 = 3

line 4:

for this we need to use the distance formula which allows us to find the distance making a third point to form a right angle triangle

point 1: (1,3)

point 2: (4,7)

point 3 (new point) : (4,3)

now we can apply the pythogorean thereum (C squared = B squared + A squared) with the following lines.

line 1: (1,3) - (4,7)

line 2: (1,3) - (4,3)

line 3: (4,3) - (4,7)

line 1 squared = line2 squared + line 3 squared

calculate length of line 2 and 3

line 1 squared = (4 - 1) squared + (7 - 3) squared

line 1 squared = 3 squared + 4 squared

line 1 squared = 9 + 16

line 1 squared = 25

root both sides

line 1 = 5

add all the liens together

6 + 4 + 3 + 5 = 18

8 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago