Answer: (4, 3)
Step-by-step explanation:
The formula for coordinate of the mid point is given as :
Mid point = (
, 
)
= 9
= -1
= 9
= -3
Substituting the values into the formula , we have :
Mid-point = (
, 
)
Mid-point = ( 
, 
)
Mid - point = ( 4 , 3)
The solution is y = -5
What is Quadratic Equation?
A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c = 0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
Given data ,
Let the function be f ( x ) = y
And , y = x² + 2x - 8
So , f ( x ) = x² + 2x - 8
Substituting the value for x in the equation , we get
When x = -3
f ( -3 ) = ( -3 )² + 2( -3 ) - 8
= 9 - 6 - 8
= 9 - 14
f ( -3 ) = -5
When x = 1
f ( 1 ) = ( 1 )² + 2( 1 ) - 8
= 1 + 2 - 8
= 3 - 8
f ( 1 ) = -5
Hence , the value of y = -5
To learn more about quadratic equation click :
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well, let's start off by doing some grouping, what we'll be doing is so-called "completing the square" as in a perfect square trinomial, since that's what the vertex form of a quadratic uses.
well, darn, we have a missing number for our perfect trinomial, however let's recall that in a perfect square trinomial the middle term is really the product of 2 times the term on the left and the term on the right without the exponent, so then we know that
well then, that's our mystery guy, now, let's recall all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add 3², we also have to subtract 3².
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x) = (x^2+6x)+14\implies f(x) = (x^2+6x+3^2-3^2)+14 \\\\\\ f(x) = (x^2+6x+3^2)+14-3^2\implies f(x) = (x+3)^2+5~\hfill \stackrel{vertex}{(-3,5)}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20f%28x%29%20%3D%20%28x%5E2%2B6x%29%2B14%5Cimplies%20f%28x%29%20%3D%20%28x%5E2%2B6x%2B3%5E2-3%5E2%29%2B14%20%5C%5C%5C%5C%5C%5C%20f%28x%29%20%3D%20%28x%5E2%2B6x%2B3%5E2%29%2B14-3%5E2%5Cimplies%20f%28x%29%20%3D%20%28x%2B3%29%5E2%2B5~%5Chfill%20%5Cstackrel%7Bvertex%7D%7B%28-3%2C5%29%7D)
Answer:
292 feet
Step-by-step explanation:
If Emily walked round the two rectangular parks, she walked round the perimeter of the parks.
the total distance she walked can be determined by calculating the perimeter of each of the park and adding the perimeters together
Perimeter of a rectangle = 2 x ( length + breadth)
Perimeter of the first park = 2 x (54 ft + 38 ft) = 184 ft
Perimeter of the second park = 2x (32 + 22) = 108 ft
Sum of the perimeters = 184 ft + 108 ft = 292 ft
