0.275÷0.25 with working<br> plsss its very urgent!!!!

In a city known for many tech start-ups, 311 of 800 randomly selected college graduates with outstanding student loans currently

Allushta [10]

Answer:

Null hypothesis: $p_{1} - p_{2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

$z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)(\frac{1}{800}+\frac{1}{800})}}=-1.182$

$p_v =2*P(Z$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.

Step-by-step explanation:

1) Data given and notation

$X_{1}=311$ represent the number college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

$X_{2}=334$ represent the number college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

$n_{1}=800$ sample 1

$n_{2}=800$ sample 2

$p_{1}=\frac{311}{800}=0.389$ represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

$p_{2}=\frac{334}{800}=0.418$ represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} - p_{2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{311+334}{800+800}=0.403$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)(\frac{1}{800}+\frac{1}{800})}}=-1.182$

4) Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.

6 0

3 years ago

Suppose a basketball team had a season of games with the following characteristics:

Masteriza [31]

Answer:

Hello Sir/ Mam

YOUR REQUIRED ANSWER IS 18.6%

Variables defined in the question:

H - Home - Games

W - Winning Games

Now, given:

P(H0.62 PW)0.22

P(W\mid H)=0.30

Required : Of all the games, percentage of games that were at home wins.

Hence, required :

P(W\cap H)

Now, we know that:

P(W\mid H)=\frac{P(W\cap H)}{P(H)}

0.3=\frac{P(W\cap H)}{0.62}

Hence,

P(W\cap H)=0.3*0.62=0.186=18.6\%

I hope this solves your doubt.

Feel free to comment if you still have any query.

Do give a thumbs up if you find this helpful.

Step-by-step explanation:

5 0

3 years ago

Tanya writes the number 7.05. Bryce says he can write a different number using the same digits. Is he correct?

Bad White [126]

Yes, actually a couple:
different number with same digits (ex):

7.05
7.50
5.07
5.70
0.57
0.75
705
70.5
75
750
570

etc

hope this helps

8 0

3 years ago

Two angles in a triangle measure 102 degrees and 67 degrees. What is the measure of the third angle?

liraira [26]

All u have to do is 102-67

3 0

4 years ago

Read 2 more answers

Twelve students took a test and their average score was 85. However, Bob was sick that day. after Bob took the test, the average

Anestetic [448]

Given:

Total number of students, n=12.

The average score of 12 students, a=85.

After Bob took the test, the number of students attended the test, N=13.

The new average score, A=82.

The total score of 12 students is the product of their average score and the number of students.

Hence, the total score of 12 students is,

$\begin{gathered} t=a\times n \\ t=85\times12 \\ t=1020 \end{gathered}$

The total score of 13 students is,

$\begin{gathered} T=A\times N \\ T=82\times13 \\ T=1066 \end{gathered}$

Now, Bob's score can be calculated as,

$\begin{gathered} B=T-t \\ B=1066-1020 \\ B=46 \end{gathered}$

Therefore, Bob's score on the test is 46.

8 0

2 years ago

0.275÷0.25 with working plsss its very urgent!!!!