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Liula [17]
3 years ago
12

Help please?-LeSandwich

Mathematics
1 answer:
harina [27]3 years ago
3 0
the answer is 10 quarts hope it helped
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Which point is NOT a solution of the inequality graphed below?
Murljashka [212]

Answer:

a

Step-by-step explanation:

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Hello my name is lay lay today I am going to ask people this question if you answer this question you are my social studies part
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ok so regrouping is when the top number of a equation is like for EXAMPLE 3 minus 6 ok so 3 is lower than six so the number on the left side you cross that out and you add it to the number that was on top which would make it 13 in this case so 13 minus six is 7 and that’s regrouping

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3 years ago
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4x - 4 + 112 = 23x - 6
Debora [2.8K]

Answer:

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Step-by-step explanation:

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2 years ago
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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
What is the system of inequalities associated with the following graph?
slamgirl [31]

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = \frac{(-3-3)}{0-(-2)}

= \frac{-6}{2}= -3

So the equation of line will be y= -3x -3

And the inequality should be y\geq -3x-3

Or 3x +y \geq -3

And the other line passes through (-2,3) and (0,2)

So the y intercept is b=2

and the slope is m= \frac{2-3}{0-(-2)} = \frac{-1}{2}

So the equation of line will be y= \frac{-1}{2} x +2\\and the inequality should be  y \leq \frac{-1}{2} x+2

Or

2y +x \leq 4

So answer is 3x +y \geq -3,  x+2y\leq 4

6 0
3 years ago
Read 2 more answers
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