Let present age of women be x.
Then,Present age of her daughter be y.
According to the question,
<u>Two years ago,</u>
Woman age = x - 2
Her daughter age = y - 2
Woman was 7 times old as her daughter. [ Given ]
x - 2 = 7 ( y - 2 )
=> x - 2 = 7y - 14
=> x - 2 + 14 = 7y
=> x + 12 = 7y ....( i )
<u>A</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>Three years </u>,
Woman age = x + 3
Her daughter age = y + 3
she would be 4 times old as the girl. [ Given ]
x + 3 = 4 ( y + 3 )
=> x + 3 = 4y + 12
=> x = 4y + 12 - 3
=> x = 4y + 9....( ii (
Now,
★ Putting the value of x = 4y + 9 from equation ( ii ) in equation ( i ),we get
x + 12 = 7y
=> 4y + 9 + 12 = 7y
=> 21 = 7y - 4y
=> 21 = 3y
=> 3y = 21
=> y = 21/3
=> y = 7
And,
x = 4y + 9
★ Putting the value of y in equation ( ii ), we get
x = 4 × 7 + 9
x = 28 + 9
x = 37
Hence, the present age of women is 37 years and her daughter age is 7.
Answer:20πmm
Step-by-step explanation:
each pencil diameter=10mm
each pencil diameter=radius Of The band
Radius of band=10mm
Circumference of band=2 x π x radius
Circumference of band=2xπx10
Circumference of band=20π
The length of band is the circumference Of The band
There length of band is 20πmm
Step-by-step explanation:
Assuming the readable scores are:
100, 82, 95, __ , 90, 81, 75, 83, __
We know the mean (or average) is 85, so:
85 = (100 + 82 + 95 + x + 90 + 81 + 75 + 83 + y) / 9
765 = 606 + x + y
159 = x + y
We know the lowest score is 75, so x and y must be at least 76. Possible answers are:
76 and 83
77 and 82
78 and 81
79 and 80
80 and 79
81 and 78
82 and 77
83 and 76
Answer:
A) (0,0)
Step-by-step explanation:
Plug in 0 for x to solve for y. y=4(0).
4(0)=0, so y=0.
-5 + -3 the answer is -8 because its just like adding
