3 years ago

Help please?-LeSandwich

Mathematics

1 answer:

harina [27]3 years ago

3 0

the answer is 10 quarts hope it helped

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It will mean a whooole lot for me if you answer

LuckyWell [14K]

Answer:

1 ) 180 - 71 = 109

2) 5x +x = 180 ; 6x = 180 ; x = 180/6 = 30

3) 90

4) x + 6x+8 + x+12 = 180 ; 8x + 20 = 180 ; 8x = 160/8= 30

5) 180 -110 = 70

6) m = 180- 119 = 61

7) 90

8) 11y - 36 = 63 ; y = 99/11 = 9

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(Q7) 180

(Q8) 2x+x = 3x = 90 ; x = 90/3 = 30

(Q15) 157

(Q16) 5x + 4 + (x-2) + (3x+7) = 180

9x +9 = 180 ; x = 171 / 9 = 19

I hope im right!!

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3 years ago

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Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all

Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

$\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\$

= $\frac{(-1)*(omega + 1)}{omega^{2} }$

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= $\frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2} }$

Rearranging and simplifying:

= $\frac{-1}{omega } + \frac{-1}{omega^{2} }$

= $\frac{(-1)*(omega + 1)}{omega^{2} }$

= $\frac{(-1)*(- omega^{2} )}{omega^{2} }$

= 1 Answer

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