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lubasha [3.4K]
3 years ago
8

Need help , can someone help me?

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
3 0

The answer is B.

Step-by-step explanation:

The min and max are 6 and 30, which is the same for all of the choices.

We need to find the median, which since there's an even number of elements we take the mean of the two elements in the middle (eg 20 and 22), which gives us 21. So the middle whisker will be on 21, so we know the answer is B or D.

Next, we need to find the upper and lower quartile. For these, we take the median again, but this time it's the median of the upper and lower halves (split by our median of 21). So, for the lower half, we have 6, 7, 9, 9, and 20. Since there's an odd number of elements this time, we just take the middle element, which is 9, so that's the lower whisker.

Then we do the same for the upper quartile. The upper half (above 21) is 22, 26, 28, 29, and 30. Since the number of elements is odd again, we just take the middle element, which is 28, so that is the upper whisker.

Plot the lower and upper whiskers and the median and you get graph B.

Dafna11 [192]3 years ago
3 0
The answer is b because that’s just the answer
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Hello,
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8 0
3 years ago
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A rectangular patio has a length that is 4 times its width and has an area of 5000 square feet. What is the width of the patio?
dimaraw [331]

\bf \underline{ \underline{Given : }}

  • A rectangular patio has a length that is 4 times its width.

  • Area of rectangular patio is 5000 square feet.

\bf \underline{ \underline{To  \: be  \: calculated :  }}

Calculate the width of the patio.

\bf \underline{ \underline{Solution : }}

Let the width be a.

Then,Length = 4a

<u>According</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>question</u><u>, </u>

<u>\sf \: Area  \: of \:  rectangle = 5000 \:  ft {}^{2}</u>

\sf \implies \: Length  \times  Width  = 5000

Substituting the values of Length and width, we get..

\sf \implies 4a \times a = 5000

\sf \implies4 {a}^{2}  = 5000

\sf\implies \:  {a}^{2}  =  \cancel \dfrac{5000}{4}

\sf\implies \:  {a}^{2}  = 1250

\sf \implies \: a =  \sqrt{1250}

\sf \implies \: a = 35.35 \:  \: (approx)

\sf\therefore \: The \: width  \: of \:  rectangular  \: patio \:  is  \: 35.35 \: ft

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3 years ago
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I hope this helps you!</span>
8 0
3 years ago
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