3,500 kilometers in one day
Add 3x and 2x together to get 5x. Then do 88+108-6 and you get 190. To find x now all you have to do is use 5x+190=360 to get x.
360 -190= 170 now you have 5x=170 divide 170/5 and that will give u the value of x.
Inequalities are used to show the relationship between unequal expressions.
The inequalities that represent the maximum weights are:
- <em>2 axles - </em>
<em>.</em> - <em>3 axles - </em>
<em>.</em> - <em>4 axles - </em>
<em>.</em>
<em />
Let the maximum weight be represented with x
In inequality, maximum means less than or equal to i.e. 
<u>(a) 2 axles</u>
The maximum weight, here is 40000.
So, the inequality is:
<u>(b) 3 axles</u>
The maximum weight, here is 60000.
So, the inequality is:
<u>(c) 4 axles</u>
The maximum weight, here is 80000.
So, the inequality is:
<em>See attachment for the graphs of each inequality</em>
Read more about inequalities at:
brainly.com/question/11612965
Answer:
A
Step-by-step explanation:
Answer:
We <em>fail to reject H₀ </em>as there is insufficient evidence at 0.5% level of significance to conclude that the mean hours of TV watched per day differs from the claim.
Step-by-step explanation:
This is a two-tailed test.
We first need to calculate the test statistic. The test statistic is calculated as follows:
Z_calc = X - μ₀ / (s /√n)
where
- X is the mean number of hours
- μ₀ is the mean that the sociologist claims is true
- s is the standard deviation
- n is the sample size
Therefore,
Z_calc = (3.02 - 3) / (2.64 /√(1326))
= 0.2759
Now we have to calculate the z-value. The z-value is calculated as follows:
z_α/2 = z_(0.05/2) = z_0.025
Using the p-value method:
P = 1 - α/2
= 1 - 0.025
= 0.975
Thus, using the positive z-table, you will find that the z-value is
1.96.
Therefore, we reject H₀ if | Z_calc | > z_(α/2)
Thus, since
| Z_calc | < 1.96, we <em>fail to reject H₀ </em>as there is insufficient evidence at 0.5% level of significance to conclude that the mean hours of TV watched per day differs from the claim.
