Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:

By the Central Limit Theorem




Z = 2:




The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
Answer:
36 crackers
Step-by-step explanation:
If he normally eats 8 crackers every weekday, he consumes about 40 crackers.
On the last day however, he dropped 4, so he only ate 4.
8 * 4 = 32
32+ 4
= 36
Answer:
Step-by-step explanation:
[1,2]
local maxima means curve is curved downwards.
in [1,2] it is curved downward.
Answer:
-7
Step-by-step explanation:
4 + (-11)
=> {since, positive x negative = negative}
=> 4 - 11
=> -7