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3 years ago

Expand 5x(2x-5) im new plz answer dis XD

2 answers:

7 0

To expand it, you just have to multiply the first by what's in each part of the parenthetical elements. so, 10x² - 25x. This is 5x times 2x - 5x times 5.

olganol [36]3 years ago

3 0

10x*-25x

*=squared

Hope this helps!

You might be interested in

If the geometric mean of a and 34 is 6 sqrt(17) find the value of a

Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, $(n_1, n_2, ..., n_n)$ , is given by:

$G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}$

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

Two elements(n = 2), a and 34.
$G = 6\sqrt{17}$

Thus:

$\sqrt{34a} = 6\sqrt{17}$

We find the square of each side, so:

$(\sqrt{34a})^2 = (6\sqrt{17})^2$

$34a = 36\times17$

Simplifying both sides by 17:

$2a = 36$

$a = \frac{36}{2}$

$a = 18$

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0

3 years ago

Find the value of each variable:

Leona [35]

Answer:

5√3 = b

5 = d

10√3 = a

15 = c

Step-by-step explanation:

Sin60° = opp/hyp

sin60° = b/10

10sin60° = b

5√3 = b

Cos60° = adj/hyp

Cos60° = d/10

10Cos60° = d

5 = d

Sin30° = opp/hyp

Sin30° = 5√3/a

a = 5√3/Sin30°

a = 10√3

Tan30° = opp/adj

Tan30° = 5√3/c

c = 5√3/tan30°

c = 15

3 0

3 years ago

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago

2. The prices of several different cereals are given below. Find the mean, median, mode, MAD, and IQR of these values. Which mea

Maru [420]

Mean = $ 4. 72

Median = $ 4. 5

Mode = No mode

MAD = $ 4. 8

IQR = $ 0. 5

Measure of center = $ 4. 5

Measure of variability = $ 2. 50

<h3>How to determine the values</h3>

Given the data;

$3.50, $4.25, $6, $4.75, $5.80, $4

Mean = sum of data/ number of data values

Mean = $\frac{3. 50 + 4. 25 + 6 + 4. 75 + 5. 80 + 4}{6}$

Mean = $ 4. 72

Median is the number in the center when the data is arranged in an ascending order

$3. 50, $4, $4. 25, $4. 75, $5. 80, $6

Median = $\frac{4. 25 + 4. 75}{2}$

Median = $ 4. 5

Mode is the number with the highest repeats.

From the given data, none of the numbers was repeated.

Thus, there is no mode.

MAD, mean absolute deviation = |data value - mean|

MAD = $|(3. 50 - 4. 72) + (4. 25 - 4. 72) + (6 - 4. 72) + (4. 75 - 4. 72) + (5. 80 - 4.72) + (4- 4. 72) |$

MAD = $1. 22 + 0. 47 + 1. 28 + 0. 03 + 1. 08 + 0. 72$

MAD = $ 4. 8

IQR, interquartile range = Quartile 3 - quartile 1

IQR = 4. 75 - 4. 25

IQR = $0. 5

Note that the mean and median are the most common measures of center.

A measure of variability is a single number that is used to describe the spread of a data set

The measure of the center best for the data is the median = $4. 5

Measure of variability = range = highest value - lowest value = $6 - $3. 50 = $2. 50

Learn more about mean here:

brainly.com/question/20118982

#SPJ1

5 0

2 years ago

romanna [79]

<h3>Answer:</h3>

room 3 or 4

<h3>Explanation:</h3>

We assume the inequalities tell the rooms that were checked and found empty.

The solution to 3) is ...

... 2x + 3 > 11

... 2x > 8 . . . . . subtract 3

... x > 4 . . . . . . .divide by 2

The solution to 4) is ...

... -3x > -9

... x < 3 . . . . . . divide by -3

Thus, rooms greater than 4 and less than 3 were found empty. Rooms 3 and 4 were not checked, so either one could hold Nessie.

_____

The other inequalities have solutions that are already covered by the solutions to these.

1) x < -1 . . . . after subtacting 4

2) x > 5 . . . . after multiplying by 5

8 0

3 years ago