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V125BC [204]
3 years ago
6

Why do interest rates on loans tend to be higher in a strong economy than in a weak one?

Mathematics
2 answers:
BartSMP [9]3 years ago
8 0

the answer is A.

 <em>Credit markets increase in a strong economy, and with increased demand come increased prices.</em>

julia-pushkina [17]3 years ago
3 0

A strong economy can be defined as an economy which has a strong industrial base, good shares prices, vast industrialization, high GDP etc.

A strong economy has high credit rates because when the demand is high, the prices are high. When the demand is less, the prices are less.

So, option A: credit markets increase in a strong economy, and with increased demand come increased prices. - is the correct answer.

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Write the point-slope form of an equation of the line through the points (-2, -3) and (-7, 4).
Ivenika [448]
Answer:
7x+5y +29= 0
Step-by-step explanation: first we have to find slop of the line that is.( Y2-Y1)/x2-x1
M = slope = 4+3)/-7+2
M= 7/-5
Equation of line y - y 1 = M (X - X1)
Y+3 = 7/-5 (x+2)
7x + 5y +29 =0 Ans .

4 0
1 year ago
A researcher wondered whether drivers treat bicycle riders differently when they wear helmets. He rigged his bicycle with an ult
andrew-mc [135]

Answer:

In this case study we have following groups:

1. Population: It had all the cars which passed the bicyclist. Out of which 3000 cars were taken.

2. Who:  Each instance of a car passing a rider, means the drivers passing by.

That is the 3000 cars which passed the researcher on his bicycle.

3. What: The distance at which cars pass the bicycle rider. The distance the drivers stayed away from his bike.

3 0
3 years ago
What is the perimeter of the polygon?
mr_godi [17]
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B




6 0
3 years ago
Find the range for the domain {-3, 1,4.5} f(x) = 2x
exis [7]

Answer:

Step-by-step explanation:

f(x) = 2x2

Range = {f(-3), f(1), f(4), f(5)} = {18, 2, 32, 50}

5 0
2 years ago
Look at the three dimensional solid below
Sever21 [200]

Answer:

A.

Step-by-step explanation:

3 0
3 years ago
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