Answer: hi im mongraal
Step-by-step explanation:
In mathematics, a cube root of a number x is a number y such that y³ = x. All nonzero real numbers, have exactly one real cube root and a pair of complex conjugate cube roots, and all nonzero complex numbers have three distinct complex cube roots. For example, the real cube root of 8, denoted ³√8, is 2, because 2³ = 8, while the other cube roots of 8 are −1 + √3i and −1 − √3i. The three cube roots of −27i are 3i, 3√(3)/2-3/2i, and -3√(3)/2-3/2i.
(sorry if it's too late and you've already figured it out, but here you go anyway)
The easiest way to do this is to start by FOILing then add.
So just start with (x-1)(x-1)
(x-1)(x-1)
Front: (x*x) = x^2
Outer: (x*-1) = -x
inner: (-1*x) = -x
Last: (-1*-1) = 1
Added: x^2 -2x +1
Now take that answer and do the same thing with (x-1). It's basically the same thing, just with an added thing you need to multiply.
(x-1)(x^2-2x+1)
(x*x^2) = x^3
(x*2x) = 2x^2
(x*1) = x
(-1*x^2) = -x^2
(-1*-2x) = 2x
(-1*1) = -1
Now add everything together:
x^3+2x^2+x-x^2+2x-1
The answer is:
x^3+x^2+3x-1
Answer:
a
Step-by-step explanation:
just tryna get brainley points
Answer:
1 + 1= 2
Step-by-step explanation:
because if u add 1 + 1 u will get 2
Hello,
if n=15: (4,1),(31,8),(244,63)
if n=7: (8,3),(127,48),(2024,765)
if n=99: (10,1),(199,20),(3970,399)
(Pell 's equation)