2. Write (2+5i)(3-1) as a complex number in standard form a+bi. real part + imaginary part

Mathematics

1 answer:

Burka [1]2 years ago

5 0

Answer:4+10i

Step-by-step explanation:

6+15i-2-5i

4+10i

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Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form

almond37 [142]

Answer:

$=14a^5+14a^4-10a^3-16a$

Step-by-step explanation:

$\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4$

$\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a$

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2 years ago

R−5r−6s+8s−15 what is the answer for this equation

weeeeeb [17]

Step-by-step explanation:

r-5r-6s+8s-15

-4r+2s-15

= 2s-4r-15

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2 years ago

A. Determine the y-intercept by<br> substituting 0 for x

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What’s the question?

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Aliun [14]

-1/2 / 3/4 =

The first step is to flip the second fraction and change division to multiplication. Then multiply straight across.

-1/2 x 4/3 = -4/6

In simplified form:
-4/6 = -2/3

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3 years ago

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Answer:

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