(3x^2- 5)(x^2+2) that is the answer
Answer:
Step-by-step explanation:
a) Data and Calculations:
Estimated useful life of a computer = 5 years
Cost of a computer purchased = $2,400
Annual depreciation expense = $480 ($2,400/5)
This means that the business owner chooses to spread (expense) the cost of the computer over 5 years at a rate of $480.
After 3 years, the cost already expensed = $1,440 ($480 * 3)
The Remaining value of this computer after 3 years of use will be $960 ($2,400 - $1,440).
b) Depreciation is an accounting method for spreading (or expensing) the cost of a long-term asset over its useful life.
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
Answer:
y= 3/2x- 4
Step-by-step explanation:
3/2 = mx
b= -4
y=mx+b
