Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
197.625
Step-by-step explanation:
6324/32 = 1581 =8
Answer:
.75 < 7/8
Step-by-step explanation:
Lets change the decimal to a fraction
.75 = 75/100
Divide the top and bottom by 25
75/100 = 3/4
Multiply by 2/2
3/4*2/2 = 6/8
6/8 < 7/8
so .75 < 7/8