Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
Step-by-step explanation:
Total number of miles is 700.
On the first day, they drove 6 and 2/3 hours. We would convert 6 and 2/3 hours to improper fraction. It becomes 20/3 hours. On the second day, they drove 5 and 3/4 hours. Converting to improper fraction, it becomes 23/4 hours. Total number of hours that they drove during the first two days is the sum of hours driven on the first day and hours driven on the Second day. It becomes
20/3 + 23/4 = (80 + 69)/12
= 149/12 hours
3.0? Im not sure but i this so
I can't answer this because I don't know what she was starting with
