The graph on the top right is non linear bc it breaks pattern in y column
His test average is 92.42424242424242 which rounds up to 92.424.
The question that is asked is pretty straight forward. Only thing that needs to be found is the number of 30 in the number 600. By dividing 600 by 30 we can arrive at the desired result.
Number of 30 in 600 = 600/30
= 60/3
= 20
So there are 20 number of 30s in the number 600. This method can be used to find answers to several other similar kind of questions like the number of 10s in 1000.Following the same procedure we get
Number of 10 in 1000 = 1000/10
= 100
answer = the elder bother is 17 and the younger one is 15
constructive odd integers= 15 and 17
17×15= 255
255+38 = 293
Square root of 293 = 17
The g(x) is slid over from f(x) 5 units I think the answer would be c
