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Pepsi [2]
4 years ago
11

Which is the rate of change for the interval between –6 and –3 on the x-axis?

Mathematics
2 answers:
Naya [18.7K]4 years ago
8 0
A. -2 is the correct answer for the rate of change
aalyn [17]4 years ago
7 0

Answer:

A is the answer to this question. Hope this helps!

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What is 4/9÷2/3 show work please!
alexira [117]
\frac{4}{9} ÷ \frac{2}{3}

First, apply the rule: a ÷ \frac{b}{c} = a × \frac{c}{b}
\frac{4}{9} × \frac{3}{2}
Second, apply the rule: \frac{a}{b} × \frac{c}{d} = \frac{ac}{bd}
\frac{4x3}{9x2}
Third, multiply 4 × 3 to get 12, and 9 × 2 to get 18.
\frac{12}{18}
Fourth, find the GCF of 12 and 18.
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 18: 1, 2, 3, 6, 9, 18
The GCF is 6.
Fifth, divide the numerator by the GCF. 
12 ÷ 6 = 2
Sixth, divide the denominator by the GCF. 
18 ÷ 6 = 3
Seventh, rewrite your fraction.
\frac{2}{3}

Answer as fraction: \frac{2}{3}
Answer as decimal: 0.6667

7 0
3 years ago
Read 2 more answers
lana is using a can opener to open a can of soup every time she twists the knob of the can opener the can turns 36 degress
vlabodo [156]
It takes 10 turns. There is 360 degrees in a circle, 360/36=10. 

Answer= 10 turns

7 0
4 years ago
Which represents the number of centimeters that are in x meters?
Olegator [25]

the answer is D because one meter equals 100 centimeters.

3 0
4 years ago
Read 2 more answers
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
jackson hass $200 in his bank account and is saving $15 per week. Cooper has $525 in his bank account and spends $10 per week. W
Degger [83]

Answer:

Step-by-step explanation:

wow

3 0
3 years ago
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