Which of the following shows the graph of y = 2 l n x On a coordinate plane, a curve starts at (0, negative 2) in quadrant 4 and
then increases into quadrant 1 and approaches y = 3. On a coordinate plane, a curve starts in quadrant 4 and then curves up into quadrant 1 and approaches y = 5. It crosses the x-axis at (1, 0). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 1). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 2).
The answer to this question can be defined as follows:
Step-by-step explanation:
Given:
In the above choices it is clearly defined from the above equation that output rises in the first quadrant, the value of f(x) tends to be zero and increases into another second quadrant.
For x = 0, y, once again, has become 1, that is the function passes the y platform at (0,1).
Therefore an exponential function reaches y = 0 in quadrant 1 on a coordinate plane and rises into quadrant 2.
(0,1) stage is the temperature at which the y-axis intersects.
