All categories

3 years ago

I tried, but can't get any further

Mathematics

1 answer:

san4es73 [151]3 years ago

8 0

The next step would be to recognize your expression as a difference of squares:

$64z^2-1=(8z)^2-1^2$

We have a neat rule for factorization of a difference of squares:

$a^2-b^2=(a-b)(a+b)$

So you would have

$64z^2-1=(8z-1)(8z+1)$

You might be interested in

2. Which answer is equivalent to "y less than 2 times 7"?

mart [117]

The answer is to the equation is b

5 0

2 years ago

Multiply the polynomials show steps

Karo-lina-s [1.5K]

Answer:

3 $a^{4}$ + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.

(a² + 4a - 6) × (3a² - a + 3) =

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3}

Now we can evaluate the terms in the brackets.

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =

3 $a^{4}$ + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

We can open the brackets now. One plus and one minus makes a minus.

3 $a^{4}$ + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3 $a^{4}$ -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

Evaluate like terms.

3 $a^{4}$ -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3 $a^{4}$ + 11a³ - 7a² + 18a - 18

5 0

3 years ago

Difference of 8 Let's dig into this and find out for sure. First think of two numbers that have a difference of 8. Type the LARG

Serhud [2]

Answer:

16

Step-by-step explanation:

We need to find 2 numbers that have a difference of 8.

Let take's 16 and 8.

As we know :

⇒ 16 - 8

⇒ 8

The larger of these 2 numbers is 16

5 0

1 year ago

Find a quadratic function that includes the set of values below. (0,9). (2,15) (3,12)

nlexa [21]

Answer:

$f(x) = -2x^2 + 7x + 9$

Step-by-step explanation:

$f(x) = ax^2 + bx + c\\f(0) = 9 => c = 9;\\f(2) = 15 = 4a + 2b + 9 2a + b = 3\\f(3) = 9a + 3b + 9 = 12 3a + b = 1\\Subtract the second equation from the first:\\-a = 2 => a = -2; b = 7; c = 9\\f(x) = -2x^2 + 7x + 9$

3 0

3 years ago

Given f(x) =3x-7, find f(x+1)+f(1)

ELEN [110]

Answer:

3x - 8

Step-by-step explanation:

To find f(x + 1) substitute x = x + 1 into f(x)

f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Similarly

f(1) = 3(1) - 7 = 3 - 7 = - 4

Hence

f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8

3 0

3 years ago