Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
Answer:
<h2><u>ᎪꪀsωꫀᏒ </u></h2>
➪ (D) I and II
Step-by-step explanation:
hope it's helpful to you
First distribute
4x=2(x-5)-2
4x=2x-10-2
4x=2x-12
2x=-12
x=-6
You add 13 and 8 it gets 21 so for X its 13
3 because if you have 9 calicos and for every three you have one it would be 3x3 (calico) 3x1(grey)
