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2 years ago

A= (5/2) b= (-1/7) Work out 2a + b as a column vector.

Mathematics

1 answer:

Svet_ta [14]2 years ago

4 0

Answer:

0.35714285714

You can search for any mathematical expression, using functions such as: sin, cos, sqrt, etc. You can find a complete list of functions here.

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0.35714285714

You can search for any mathematical expression, using functions such as: sin, cos, sqrt, etc. You can find a complete list of functions here.

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Draw a tape diagram to represent the following equation: 3x + 15 = 90

Vikentia [17]

Answer:

Step-by-step explanation:

Subtract 15 from both sides then divide by 3.

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Write 1,270 in expanded form

Vikentia [17]

Answer:

1,000 + 200 + 70

Step-by-step explanation:

Expanded form is a way of writing numbers to see the math value of individual digits.

so for example:

5,000 + 300 + 20 + 3

is 5,323.

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3 years ago

If two distinct lines intersect, which is NOT necessarily true?

Inessa05 [86]

The lines are perpendicular.

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3 years ago

Solve for k. 10 1323 3 9 CAN U HELP PLEASE

Doss [256]

Answer:

Step-by-step explanation:

k/9=10/3 multiply both sides by 9

k=90/3

k=30

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2 years ago

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A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago