Sum/Difference of 2 monomials is (in simplest terms) a monomial when the 2 monomials are 'like terms
Answer:
Step-by-step explanation:
Given:
The original function is given as:
The above function is stretched vertically by a factor of 2 to form the graph of 
.
According to the rule of function transformations, when the graph of a function is stretched in the vertical direction by a factor of 'C', where, 'C' is a number greater than 1, then the function rule is given as:
Therefore, the function is multiplied by a factor of 'C' to get the equation of the stretched function.
Here, the the value of 'C' is 2. So, the equation of is given as:
![g(x)=2f(x)\\g(x)=2[2(3)^{x+1}+4]\\g(x)=4(3)^{x+1}+8](https://tex.z-dn.net/?f=g%28x%29%3D2f%28x%29%5C%5Cg%28x%29%3D2%5B2%283%29%5E%7Bx%2B1%7D%2B4%5D%5C%5Cg%28x%29%3D4%283%29%5E%7Bx%2B1%7D%2B8)
Therefore, the equation of is .
Red bricks : Grey bricks
5 : 2
Total parts = 5 + 2 = 7
7 parts = 224
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Find 1 part:
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1 part = 234 ÷ 7
1 part = 32
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Find 5 parts:
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5 parts = 32 x 5
5 parts = 160
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Answer: 160 Red bricks
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Answer:
Finding the missing number is fairly simple and can be done in a few short steps. I will show you using the 21 / __ fraction.
First, divide the included number by its corresponding number in the original fraction.
21 ÷ 3 = 7
To find what the denominator of this would be, multiply 4 by 7.
4 * 7 = 28
The fraction would be 21 / 28.
This works with both numerators and denominators. If you need more of the answers just ask in the comments.
