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Vlad1618 [11]
3 years ago
7

8 is 15% of what number

Mathematics
1 answer:
padilas [110]3 years ago
5 0
(x (15))/100 = 8
x(15) = 800
x = 800/15 = 53,3333 ( just take 53 )
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Anna divided a sheet of paper into 5 equal sections in color 3 of the sections blue what percent of the paper did she color​
e-lub [12.9K]
60/100 is 3/5 so Anna colored 60% of the paper blue
4 0
3 years ago
Rhea got a new e-scooter. She wanted to show it to her friend on the way to the library.Her friend ronan's house is due north of
Zepler [3.9K]

The distance between rhea and her friend's house could be 8 km and The distance of the library from the rocks house could be 15 km.

<h3>What is Pythagoras' Theorem?</h3>

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

rhea got a new e-scooter. She wanted to show it to her friend on the way to the library.

Her friend Ronan's house is due north of her house.

After showing him the new scooter she went to the library which is due west from rocks house.

while returning back she drove 17km diagonally to her house.

By Pythagoras' theorem

|AC|^2 = |AB|^2 + |BC|^2    

Here we can assume that

AB = The distance between rhea and her friend's house.

BC = The distance of the library from rocks house.

The triplet of the 17 would be (8, 15, 17)

So, we can say that the AB could be 8 km and BC could be 15 km or vice versa.

Learn more about Pythagoras' theorem here:

brainly.com/question/12105522

#SPJ1

7 0
2 years ago
Pablo has a busy semester, and he does not want to give too much time to Statistics. So he puts off working through the course,
arsen [322]
Plan an effective strategy for working through the course
8 0
4 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
Help is appreciated. Easy I just am always confused
saveliy_v [14]

Answer:

BA=BC

Step-by-step explanation:

8 0
4 years ago
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